x^2+2(k+1)x+2(1+k^2)=0

Solution for x^2+2(k+1)x+2(1+k^2)=0 equation:

Simplifying
x2 + 2(k + 1) * x + 2(1 + k2) = 0

Reorder the terms:
x2 + 2(1 + k) * x + 2(1 + k2) = 0

Reorder the terms for easier multiplication:
x2 + 2x(1 + k) + 2(1 + k2) = 0
x2 + (1 * 2x + k * 2x) + 2(1 + k2) = 0

Reorder the terms:
x2 + (2kx + 2x) + 2(1 + k2) = 0
x2 + (2kx + 2x) + 2(1 + k2) = 0
x2 + 2kx + 2x + (1 * 2 + k2 * 2) = 0
x2 + 2kx + 2x + (2 + 2k2) = 0

Reorder the terms:
2 + 2kx + 2k2 + 2x + x2 = 0

Solving
2 + 2kx + 2k2 + 2x + x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.